Need some simple algebra help

[Flowbee V6]

Can someone please go to this link then go to page 19 of the pdf. Yes I forgot how to do algebra

http://geography.berkeley.edu/Progra...0/L5Sept10.pdf

If I had to show my work on this equation, how would I get 255k as the answer? Can someone show me how? The square root with the 4 in it scares me

[southalabama97]

Just plug the numbers in normal and solve. You will still have the 4th root over the number. To solve the 4th root just do it like this:
#^(1/4)
I came out with 254.087.

[Flowbee V6]

Originally posted by southalabama97:
Just plug the numbers in normal and solve. You will still have the 4th root over the number. To solve the 4th root just do it like this:
#^(1/4)
I came out with 254.087.

Pardon my ignorance. Does #^(1/4) mean the # multiplied by 1/4? And what did you get for the number itself, 91.3?

[southalabama97]

Originally posted by Flowbee V6:
</font><blockquote>quote:</font><hr />Originally posted by southalabama97:
Just plug the numbers in normal and solve. You will still have the 4th root over the number. To solve the 4th root just do it like this:
#^(1/4)
I came out with 254.087.

Pardon my ignorance. Does #^(1/4) mean the # multiplied by 1/4? And what did you get for the number itself, 91.3? </font>[/QUOTE]It means the number to the 1 fourth power. This is what it looked like when I put it in my calculator.
(1370/4*5.67*10^-8*(1-.31))^(1/4)

I'm getting the number under the root to be 4.16799*10^9.

Hope this helps, I'm going to bed so hopefully you can get it.