What do you do when bored at work?

[1DangerousV6]

depends..when it takes 6 men 6 days to dig six holes..are they all working on one hole together, all each working on their own hole, or in certain numbered groups working on 1 hole at a time per group?..the equation will be different based on the different labor configurations ;)

[the bandit]

Well you cant dig half a hole but if you could it would take 12 hours......and when Im bored I go to howstuffworks.com anything you want to know about how stuff works....ehh ehh [img]graemlins/rock.gif[/img]

[xX315Xx]

Originally posted by Pathogen:
this is cracking me up...

hey, its something to do, now how bout an answer and an explination ;) ...

[the bandit]

Originally posted by 1DangerousV6:
depends..when it takes 6 men 6 days to dig six holes..are they all working on one hole together, all each working on their own hole, or in certain numbered groups working on 1 hole at a time per group?..the equation will be different based on the different labor configurations ;)

;) lol

[12secondv6]

Went to lunch.... 2005 CLK500 hard top :D

[AZ3.8Camaro]

A hole is a hole. There are no half holes.

[xX315Xx]

Originally posted by AZ3.8Camaro:
A hole is a hole. There are no half holes.

i'm effin retarded, thanks for straightening that out for me

Originally posted by 12secondv6:
Went to lunch.... 2005 CLK500 hard top :D

went to lunch 95 camaro t-top ;)


it would also depend on if they had to dig a certain size hole. If they had to dig a hole 6 ft deep, and they only got to 3 ft...it's half the hole they need...

[1DangerousV6]

Originally posted by 12secondv6:
Went to lunch.... 2005 CLK500 hard top :D

went to lunch....pasta :D

[12secondv6]

In the CLK.... I had a very pretty girl (ok, she is damn hot) w/ me ;)

But... she is taken... and a good friend [img]tongue.gif[/img]

[1DangerousV6]

well..is she taken BY a good friend? lol j/k

[majeskyb]

I say nine days. The way I see it, if it takes 6 ppl to dig 6 holes in 6 days, then it takes 6 men 1 day to dig 1 hole. so one man can dig 1/6 of a hole a day 6 days=1 hole, plus 3 days=1/2 hole

[1DangerousV6]

so..

M=men, H=holes, D=days, A=answer

to find .5H=1MxA you have..

(6M=6H=6D) = (6M=1H=1D) = (1M=1/6H=1D) =

(1/6Hx3D=.5H) = (3D=.5H) = (A=3)

3 days

[MrCoffee]

Originally posted by 1DangerousV6:
so..

M=men, H=holes, D=days, A=answer

to find .5H=1MxA you have..

(6M=6H=6D) = (6M=1H=1D) = (1M=1/6H=1D) =

(1/6Hx3D=.5H) = (3D=.5H) = (A=3)

3 days

do you have any idea what you've just done to the joke?

[kristen]

i close the door to my office and watch dvd's [img]graemlins/popcorn.gif[/img] . and when some one needs me to do something they will page me and i will get back to work. then when i'm done i'll resume watching my dvd. or i'm on this site or emailing 1dangerousv6. hi scott [img]graemlins/wavey.gif[/img]

[vanbibber]

Originally posted by MrCoffee:
</font><blockquote>quote:</font><hr />Originally posted by 1DangerousV6:
so..

M=men, H=holes, D=days, A=answer

to find .5H=1MxA you have..

(6M=6H=6D) = (6M=1H=1D) = (1M=1/6H=1D) =

(1/6Hx3D=.5H) = (3D=.5H) = (A=3)

3 days

do you have any idea what you've just done to the joke? </font>[/QUOTE][img]graemlins/rofl.gif[/img] im done after reading that